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Hi,
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I am programming in Emboss but I do not understand why the buckle number 2 (see it in red) does not work.
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The problem is that the program does not pass by the buckle in red. Is it impossible to have two imbricated buckles or there is another problem ?
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I do not find the answer to my answer so, can someone help me, please ..... :-(
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Carole
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This is the code :
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//Sélection des meilleurs couples
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ajint compteur2 = 0;
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iterList3 = ajListIter(ListCoupleInit); // parcours liste couple avec score
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iterList4 = ajListIter(BestCouple); // liste contenant meilleurs couples
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ajint nbreBestCouple2 = 0;
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nbreBestCouple2 = ajListLength(BestCouple);
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ajFmtPrintF(outf,"\n nbre de meilleurs couples 2 : %d \n", nbreBestCouple2);
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//remplissage liste BestCouple
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while (ajListIterMore(iterList3))
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{
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ajFmtPrintF(outf,"\n Boucle 1 \n");
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res3 = (CoupleOlig) ajListIterNext(iterList3);
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ajint nbreBestCouple3 = 0;
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nbreBestCouple3 = ajListLength(BestCouple);
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ajFmtPrintF(outf,"\n nbre de meilleurs couples 3 : %d \n", nbreBestCouple3);
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if (compteur2 == 0)
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{
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ajFmtPrintF(outf,"\n Boucle 3 \n");
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ajListPush(BestCouple, (void *) res3);
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ajFmtPrintF(outf,"\n Boucle 5 \n");
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}
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compteur2 ++;
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while (ajListIterMore(iterList4))
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<FONT COLOR="#f80000"><B> {</FONT></B>
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<FONT COLOR="#f80000"><B> ajFmtPrintF(outf,"\n Boucle 2 \n"); </FONT></B>
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<FONT COLOR="#f80000"><B> res4 = (CoupleOlig) ajListIterNext(iterList4);</FONT></B>
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<FONT COLOR="#f80000"><B> if (res3->score <= res4->score)</FONT></B>
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<FONT COLOR="#f80000"><B> {</FONT></B>
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<FONT COLOR="#f80000"><B> ajFmtPrintF(outf,"\n Boucle 4 \n"); </FONT></B>
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<FONT COLOR="#f80000"><B> ajListInsert(iterList4, (void*) res3);</FONT></B>
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<FONT COLOR="#f80000"><B> } </FONT></B>
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<FONT COLOR="#f80000"><B> }</FONT></B>
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}
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ajint nbreBestCouple = 0;
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nbreBestCouple = ajListLength(BestCouple);
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ajFmtPrintF(outf,"\n nbre de meilleurs couples : %d \n", nbreBestCouple);
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